`64g` of an organic compound contains `24 g ` of carbon, `8gm` of hydrogen and the rest oxygen. The empirical formula of the compound isA. `CH_(2)O`B. `C_(2)H_(4)O`C. `CH_(4)O`D. `C_(2)H_(8)O_(2)`

`64g` of an organic compound contains `24 g ` of carbon, `8gm` of hydr

1.	`64g` of an organic compound contains `24 g ` of carbon, `8gm` of hydrogen and the rest oxygen. The empirical formula of the compound isA. `CH_(2)O`B. `C_(2)H_(4)O`C. `CH_(4)O`D. `C_(2)H_(8)O_(2)`
Answer» Correct Answer - C `"Elements No. of moles Simpleratio"` `C(24g)" "24//12=12" "1` `H(8g)" "8//1=8" "4` `O (32g)" "32//16=2" "1` Empirical formula `=CH_(4)O`

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`64g` of an organic compound contains `24 g ` of carbon, `8gm` of hydrogen and the rest oxygen. The empirical formula of the compound isA. `CH_(2)O`B. `C_(2)H_(4)O`C. `CH_(4)O`D. `C_(2)H_(8)O_(2)`

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