68.4 g of sugar (molecular weight = 342) is dissolved in 1000 g of water. What is (a) freezing point (b) boiling point (c) vapour pressure at 20^(@)C (d) osmotic pressure of the solution at 20^(@)C? The density of the solution at 20^(@)C is "1.024 g cm"^(-3). The vapour pressure of water at 20^(@)C is 17.633 mm. The K_(f) and K_(b) values for water are 1.873^(@) and 0.516^(@) respectively.

68.4 g of sugar (molecular weight = 342) is dissolved in 1000 g of wat

1.	68.4 g of sugar (molecular weight = 342) is dissolved in 1000 g of water. What is (a) freezing point (b) boiling point (c) vapour pressure at 20^(@)C (d) osmotic pressure of the solution at 20^(@)C? The density of the solution at 20^(@)C is "1.024 g cm"^(-3). The vapour pressure of water at 20^(@)C is 17.633 mm. The K_(f) and K_(b) values for water are 1.873^(@) and 0.516^(@) respectively.
Answer» Solution :Apply `Delta T_(f)=K_(f)m and DeltaT_(b)=K_(b)m,` Mass of solution = `1000+68.4=1068.4g`. `"VOLUME "=(1068.4)/(1.024)CM^(3)`.