1.

6a2−13a+6=?(a) (2a+3)(3a−2)(b) (2a−3)(3a+2)(c) (3a−2)(2a−3)(d) (3a+1)(2a−3)

Answer»

6a2−13a+6=?(a) (2a+3)(3a−2)(b) (2a−3)(3a+2)(c) (3a−2)(2a−3)(d) (3a+1)(2a−3)




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