7. An elevator descends into a mine shaft at the rate of 6 m/min. If t

1.	7. An elevator descends into a mine shaft at the rate of 6 m/min. If the descendstarts from 10 m above the ground level, how long will it take to reach the shaft350 m below the ground level?
Answer» Answer: 1 Hr. Step-by-step explanation: Considering the elevator to be at constant speed and the destination to be 350 m below ground level, The elevator has to travel 10m till the ground, then 350 m more. So, the TOTAL distance to travel is 360 m If the elevator's speed is 6 metres/minute, Then Time = Distance/Speed = 360/6 = 60 minutes = 1 HOUR Thus the elevator would take 1 hour to reach its destination. <><><><> brainliest plzzz...... ♡ ❣ ♡ ❣ ♡ ❣ ♡ ❣ ♡ ❣ ♡ ❣ ♡ ❣ ♡ ❣ ♡ ❣ ♡ ❣ ♡

7. An elevator descends into a mine shaft at the rate of 6 m/min. If the descendstarts from 10 m above the ground level, how long will it take to reach the shaft350 m below the ground level?

Answer»

Answer:

1 Hr.

Step-by-step explanation:

Considering the elevator to be at constant speed and the destination to be 350 m below ground level,

The elevator has to travel 10m till the ground, then 350 m more.

So, the TOTAL distance to travel is 360 m

If the elevator's speed is 6 metres/minute,

Then

Time = Distance/Speed

= 360/6

= 60 minutes

Thus the elevator would take 1 hour to reach its destination.

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brainliest plzzz......

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