7. Through a rectangular field of length 90 m and breadth 60 m, two ro

1.	7. Through a rectangular field of length 90 m and breadth 60 m, two roads are constructed which are parallel to the sides and cut each other at right angles throughthe centre of the fields. If the width of each road is 3 m, find(1) the area covered by the roads.(i) the cost of constructing the roads at the rate of 7 110 per m2.
Answer» Step-by-step explanation: Length of the road along the length of the field= 90m Breadth= 3m Area of the road= l\times bl×b =90m\times3m=270m^2=90m×3m=270m 2 Similarly, the area of the road parallel to the breadth of the field= l\times bl×b =60m\times3m=180M^2=60m×3m=180m 2 Area of the common PORTION= 3m\times3m=9m^23m×3m=9m 2 (i) Area of the two roads =270m^2+180m^2-9m^2=270m 2 +180m 2 −9m 2 =450m^2-9m^2=441m^2=450m 2 −9m 2 =441m 2 (ii) COST of constructing the roads =Rs\ 110\times441=Rs\ 48,510=Rs 110×441=Rs 48,510

7. Through a rectangular field of length 90 m and breadth 60 m, two roads are constructed which are parallel to the sides and cut each other at right angles throughthe centre of the fields. If the width of each road is 3 m, find(1) the area covered by the roads.(i) the cost of constructing the roads at the rate of 7 110 per m2.

Answer»

Step-by-step explanation:

Length of the road along the length of the field= 90m

Breadth= 3m

Area of the road= l\times bl×b

=90m\times3m=270m^2=90m×3m=270m

Similarly, the area of the road parallel to the breadth of the field= l\times bl×b

=60m\times3m=180M^2=60m×3m=180m

Area of the common PORTION= 3m\times3m=9m^23m×3m=9m

(i) Area of the two roads

=270m^2+180m^2-9m^2=270m

+180m

−9m

=450m^2-9m^2=441m^2=450m

−9m

=441m

(ii) COST of constructing the roads

=Rs\ 110\times441=Rs\ 48,510=Rs 110×441=Rs 48,510