1.

7128=2^p x 3^q x 11^r

Answer» \bold{\boxed{HEY!!!}}


HERE IS YOUR ANSWER :-


Lets FIND prime factors of 7128


7128 = 2 × 3564


= 2 × 2 × 1782


= 2 × 2 × 2 × 891


= 2 × 2 × 2 × 3 × 297


= 2 × 2 × 2 × 3 × 3 × 99


= 2 × 2 × 2 × 3 × 3 × 3 × 33


= 2 × 2 × 2 × 3 × 3 × 3 × 3 × 11


= 2³ × 3⁴ × 11¹


7128 = 2³ × 3⁴ × 11¹


But


7128 = 2^p × 3^q × 11^r


So


2³ × 3⁴ × 11¹ = 2^p × 3^q × 11^r


\bold{\boxed{p = 3 , q = 4 , r = 1}}


Discussion

No Comment Found

Related InterviewSolutions