1.

75% of a first order reaction is completed in 30 minutes . What is the time required for 93.75 % of the reaction (in minutes )

Answer»

45
120
90
60

Solution :`K = (2.303)/(t) "log" ((a)/(a-x)) , k = (2.303)/(30) "log" ((100)/(100-75))… (i)`
`k = (2.303)/(t)"log" ((100)/(100-93.75))` PUT the value of k from above equation (i) we get the value of t THEREFORE
`therefore` t = 60 min .


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