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75% of the first order reaction is completed in 30 minutes. Calculate rate constant of the reaction. |
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Answer» Solution :t= 30 min, `[R]_circ = 100,[R]` = 25 `K= 2.303 /t LOG``([R]_circ )/([R] )``K= 2.303 /t log``([R]_circ )/([R] )` t= `2.303/30 log ``100/25` K= 0.0767`xx` log 4 = 0.0767 `xx` 0.6021 `k= 0.0461 min^-1` |
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