1.

75% of the first order reaction was completed in 32 minutes. When was 50% of the reaction completed

Answer»

24 minutes
16 minutes
8minutes
4 minutes

Solution :`N = (25)/(100) N_(0)` (at t = 32 minutes)
THUS, `t = (2.303)/(0.693) XX t_(1//2) "LOG"(N_(0))/(N)`


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