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7A gaseous mixture contains CiH4 and Cals in equimolecular proportion. the weight of 224 litres of this mixture atD) 23 gNTP is:A)4.6 gB) 1.6 g

Answer»

Suppose we take 1 mole of CH4 Weight=16gm And 1mole C2H6 weight =30gm Now, 1 mole of both CH4 and C2H6 occupy 22.4L Therefore when mixed Total weight of mixture=16+30=46 Total volume of mixture=22.4+22.4=44.8L 44.8L of mixture weigh 46g So,2.24L of mixture weighs=( 46÷44.8)×2.24=2.3g



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