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(7x–4)/(3x+4)= (5x–2)/3x |
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Answer» Applying cross MULTIPLICATION method.!(7x-4)×(3x) = (5x-2)×(3x+4)21x^2-12x = 5x(3x+4) - 2(3x+4)21x^2-12x = 15x^2+20x - 6x-821x^2-15x^2 = 12x+20x-6x - 8 6x^2 = 26x - 8 6x^2 - 26x + 8 = 0Factorisation method:(6x^2 - 24x) + (-2X + 8) = 06x(X - 4) - 2(x - 4) = 0(6x-2)(x-4) = 02(3x-1)(x-4) = 0x = 1/3 and 4Hope it HELPS.!If you want, pls mark me brainliest. |
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