Saved Bookmarks
| 1. |
7y2-11/3y-2/3 this question |
|
Answer» ANSWER:Answer p(y) = 7y2 – 11Y/3 – 2/3 = 1/3 × (21y2 – 11y – 2) = 1/3 × [(7y + 1)(3y – 2)] ∴ Zeroes are 2/3, –1/7 SUM of zeroes = 2/3 – 1/7 = 11/21 –b/a = 11/21 ∴ sum of zeroes = –b/a Product of zeroes = (2/3)(–1/7) = – 2/21 c/a = (–2/3)(1/7) = – 2/21 ∴ Product = c/a |
|