1.

8.2gm of sodium acetate is heated with soda line. What is the volume of methane liberated at S.T.P?

Answer»

Solution :The reaction between SODIUM acetate and SODA lime is `CH_3COONa + NaOH underset(Delta)overset(CAO)to CH_4 + Na_2CO_3`
1 MOLE `CH_3 COONa` gives `to` 1 mole `CH_4` at STP 8.2 GM `CH_3COONa` (0.1 mole) give `to ?` `= 0.1 xx 22.4 "lit". = 2.24 "lit"`.


Discussion

No Comment Found