8.Eight times the first of three consecutive odd integers is 4 less than thrice the sum of second and third. The second integer is a)7 b)9 c)13 d)11 e)15

8.Eight times the first of three consecutive odd integers is 4 less th

1.	8.Eight times the first of three consecutive odd integers is 4 less than thrice the sum of second and third. The second integer is a)7 b)9 c)13 d)11 e)15
Answer» e three consecutive ODD INTEGERS be (x+1) , (x+3) , (x+5) So, Eight times the first number = 8(x+1)Sum of second and third number = (x+3) + (x+5)According to Sum,8 ( x + 1 ) + 4 = 3 [( x + 3 ) + ( x + 5 )] ↬8x + 8 + 4 = 3 [ x + 3 + x + 5 ] ↬ 8x + 12 = 3 ( 2x + 8) ↬ 8x + 12 = 6x + 24 ↬ 8x - 6x = 24 - 12 ↬ 2x = 12 ↬ x = 6 Second number = ⇢ ( x + 3 ) ⇢ ( 6 + 3 )⇢ 9First number = ( x + 1 ) = 7Second number = 9 Third number = 11RHS, 8 ( x + 1 ) + 4⇢ 8 [ 7 ] + 4 ⇢ 56 + 4 ⇢ 60LHS,3 [( x + 3 ) + ( x + 5 )]⇢ 3 [ 9 + 11 ]⇢ 3 ( 20 )⇢ 60So, LHS = RHS