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8) Find theco-ordinates of a centroid of triangle whose verticesare (6,2), (0,0) and ( 4,-7)​

Answer»

✫ The centroid of triangle is (10/3,-5/3). ✫

Step-by-step explanation:

As we know that,

\;\;\;\;\;\bullet\;\boldsymbol{G = \bigg(\frac{x_1+x_2+x_3}{3},\frac{y_1+y_2+y_3}{3}\bigg)}\\

Here,

  • The point of CONCURRENCE of MEDIANS of a triangle is called centroid of triangle,it is DENOTED by 'G'.
  • Vertices = (6,2), (0,0), ( 4,-7)​
  • x₁ = 6,y₁ = 2
  • x₂ = 0,y₂ = 0
  • x₃ = 4,y₃ = -7

Applying the VALUES,

\\ \dashrightarrow\sf{G = \frac{6+0+4}{3},\frac{2+0+(-7)}{3}}\\ \\ \dashrightarrow\sf{G = \frac{10}{3},\frac{-5}{3}}\\

  • ∴ The centroid of triangle is (10/3,-5/3).


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