1.

8 g of a radioactive susbtance is reduced to 0.5 g after 1 hours. The t_(1//2) of the radioactive substance is

Answer»

15 min
30 min
45 min
10 min

Solution :`N_(0) = 8g, N = 0.5 g and t = 1 HR. = 60` min. Find `t_(1//2)` by
`t = (2.303 XX t_(1//2))/(0.693) "log" (N_(0))/(N)`


Discussion

No Comment Found

Related InterviewSolutions