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8. The floor of a rectangular hall has a perimeter 15 m. If the cost of painting the four wall at the rate of 10 per m^2 is 15000, find the height of the hall.NO SPAM ANSWERS |
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Answer» n - The floor of a rectangular hall has a PERIMETER of 15 m. If the cost of painting the four wall at the rate of 10 per m ² is 15000,find the HEIGHT of the hall. Solution - Let length, BREADTH and height of the rectangular hall be l, b and h respectively. Perimeter of the floor of rectangular hall =2(l+b)Area of four walls = Area of cuboid - Area of floor - Area of topArea of four walls = 2(LB+bh+lh)-lb- lbArea of four walls= 2(lb)+2(bh)+2(lh)-2(lb)Area of four walls= 2(lh)+2(bh)Area of four walls = 2h(l+b)Area of four walls= 2h ×7.5 [by 1)]Area of four walls= 15hm²Now, Cost of painting per m²= Rs 10Cost of painting 15 h m²= Rs 10×15hTherefore the height of the hall is 100m |
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