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8. Three consecutive integers are such that when they multiplied by 2, 3 and 4 respectively, they add up 74 in increasing order |
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Answer» Let the THREE consecutive INTEGERS be N,n+1,n+2 respectively.According to the problem,2n+3(n+1)+4(n+2)=74or, 9n+11=74or, 9n=63or, n=7.So the numbers are 7,8,9. |
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