1.

80 g of impuresugar when dissolved in a litre of water gives an optical rotation of 9.9^(@) when placed in a tube of length 20 cm.If the specific rotation of sugar is 66^(@), find percentage purity of sugar solution:

Answer»

`93.75%`
`72%`
`56%`
`32%`

Solution :`C= (theta)/(l xx ALPHA), theta = 9.9^(@), l - 2.0` decimetre and `alpha = 66^(@)`
`therefore C = (9.9)/(2.0 xx 66^(@)) = 0.075 g/cc = 75 g/litre`
`therefore` purity `= (75)/(80) xx 100 = 93.75 %`.


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