82.) The amount of Mg in gms to be dissolved indilute H,So, to liberat

1.	82.) The amount of Mg in gms to be dissolved indilute H,So, to liberate H, which is justsufficient to reduce 160g of ferric oxide is1) 24 22 48 32 72 4) 96formed
Answer» Fe2O3 + 3 H2 → 2 Fe + 3 H2O Mg + H2SO4 → MgSO4 + H2 [balanced as written] (160 g Fe2O3) / (159.6882 g Fe2O3/mol) x (3 mol H2 / 1 mol Fe2O3) x (1 mol Mg / 1 mol H2) x (24.30506 g Mg/mol) = 73.1 g Mg

82.) The amount of Mg in gms to be dissolved indilute H,So, to liberate H, which is justsufficient to reduce 160g of ferric oxide is1) 24 22 48 32 72 4) 96formed

Answer»

Fe2O3 + 3 H2 → 2 Fe + 3 H2O Mg + H2SO4 → MgSO4 + H2 [balanced as written]

(160 g Fe2O3) / (159.6882 g Fe2O3/mol) x (3 mol H2 / 1 mol Fe2O3) x (1 mol Mg / 1 mol H2) x (24.30506 g Mg/mol) = 73.1 g Mg