1.

""_(84)^(210) Po to ""_(82)^(206) Pb + ""_(2)^(4) He . In the reaction , the position of Po in the periodic table is ___ A group when lead belongs to IV A

Answer»


Solution :`underset(VIA) (""_(84) PO^(210)) to underset(""_(82) Pb^(206)) + ""_(2)He^(4)`


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