._(84)^(218)Po(t_(1//2)=183 sec) decay to ._(82)Pb(t_(1//2)=161 sec) b – InterviewSolution

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1.	._(84)^(218)Po(t_(1//2)=183 sec) decay to ._(82)Pb(t_(1//2)=161 sec) by alpha-emission, while Pb^(214) is a beta-emitter. In an experiment starting with 1 mole of pure Po^(218), how many time would be required for the number of nuclei of ._(82)^(214)Pb to reach maximum ?
Answer» 147.5 247.5 182 304 Answer :B

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