""_(84)Po^(218)(t_(1//2)=3.05mins) decays to ""_(82)Pb^(214)(t_(1//2)= – InterviewSolution

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1.	""_(84)Po^(218)(t_(1//2)=3.05mins) decays to ""_(82)Pb^(214)(t_(1//2)=2.68min) by alpha-emission while Pb^(214) is a beta-emitter. In an experiment starting with 1g atom of pure Po_(218), how much time would be required for the number of nuclei of ""_(82)Pb^(214) to reach maximum?
Answer» ANSWER :`4.12mins`

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