1.

87.5% decomposition of a radioactive substance completes in 3 hours. What is the half-life of that substance

Answer»

2 hours
3 hours
90 minutes
1 hours

Solution :`(0.693)/(t_(1//2)) = (2.303)/(180) XX "log" (100)/(12.5)`
`t_(1//2) = (0.693 xx 180)/(2.303 xx 3 xx 0.3010) = 60` mini = 1 hr.


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