88. What volume is occupied at N.T.P. by(i) 1.4 g of nitrogen(ii) 6.02

1.	88. What volume is occupied at N.T.P. by(i) 1.4 g of nitrogen(ii) 6.023 × 1021 molecules of oxygen(iii) 0.2 mole of ammonia ?
Answer» i) Mole = Volume/22.4 (At S.T.P or N.T.P.) So according to this formula 1 Mole of any gas occupies 22.4 litres at N.T.P. For Nitrogen gas 1 mole = 14g so, for given 1.4 g = 1/14 × 1.4 = 0.1 mole Since 1 mole occupies 22.4 L at NTP so, 0.1 mole will occupy 22.4×0.1 L at NTP Hence 1.4 g of Nitrogen gas occupy 2.24 L at NTP. but answer is1.12 L

88. What volume is occupied at N.T.P. by(i) 1.4 g of nitrogen(ii) 6.023 × 1021 molecules of oxygen(iii) 0.2 mole of ammonia ?

Answer»

i) Mole = Volume/22.4 (At S.T.P or N.T.P.)

So according to this formula 1 Mole of any gas occupies 22.4 litres at N.T.P.

For Nitrogen gas 1 mole = 14g

so, for given 1.4 g = 1/14 × 1.4 = 0.1 mole

Since 1 mole occupies 22.4 L at NTP

so, 0.1 mole will occupy 22.4×0.1 L at NTP

Hence 1.4 g of Nitrogen gas occupy 2.24 L at NTP.

but answer is1.12 L