1.

8x+2/2x-3=4x/x-3 what is the solution​

Answer»

GIVEN :

\sf \implies \dfrac{8x + 2}{2x - 3} = \dfrac{4x}{<klux>X</klux> - 3}

To FIND :

SOLUTION :

\sf\implies \frac{8x + 2}{2x - 3} = \frac{4x}{x - 3} \\ \\ \large \sf By \: cross \: multiply \\ \\ \sf\implies(x - 3)(8x + 2) = 4x(2x - 3) \\ \\ \sf\implies 8 {x}^{2} + 2x - 24x - 6 = {8x}^{2} - 12x \\ \\\sf\implies 8 {x}^{2} - 8 {x}^{2} - 22x + 12x = 6 \\ \\\sf\implies - 10x = 6 \\ \\\sf\implies x = - \frac{6}{10} \\ \\ \large\implies \boxed{\boxed{ \sf x = - \frac{3}{5} }}


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