1.

9.65C of electric current is passed through fused anhydrous magnesium chloride. The magnesium metal thus, obtained is completely converted into a Grignard reagent. The number of moles of the Grignard reagent obtained is

Answer»

`5xx10^(-4)`
`1xx10^(-4)`
`5xx10^(-5)`
`1xx10^(-5)`

Solution :96500 COULOMBS of electric current deposits 12 g to Mg.
9.65 coulombs of electric current deposits
`(9.65)/(96500)=1.2xx10^(-3)` g of Mg
`THEREFORE` No. of moles of GRIGNARD reagent obtained
`=(1.2xx10^(-3))/(24)=5xx10^(-5)` moles


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