1.

9.7xx10^(17) atoms of iron weigh as much as 1 cc of H_(2) at S.T.P. What is the atomic mass of iron?

Answer»


SOLUTION :`"Mass of 1 cc of "H_(2)" at S.T.P."=(2.016)/(22400)=9.0xx10^(-5)g`
Thus, `9.7xx10^(17)` atoms or iron have mass `=9.0xx10^(-5)g`
`therefore" Mass of ONE mole, i.e., "6.02xx10^(23)" atoms of Fe"=(9.0xx10^(-5)xx6.02xx10^(23))/(9.7xx10^(17))=55.9g`


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