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InterviewSolution
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9. A mass of 50 g of a certain metal at 150°C isimmersed in 100 g of water at 11°C. The finaltemperature is 20°C. Calculate the specific heatcapacity of the metal. Assume that the specific heatcapacity of water is 4.2 J gl K-1voAns. 0-582 J gl K-i |
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Answer» Let subscript 1 denote solid (hot body)and subscript 2 denote water (cold body)Initial temp. of solid T₁=150°CMass of solid m₁ = 50 g = 0.05 KgInitial temp. of water T₂=11°CMass of water m₂= 100 g = 0.1 KgFinal temp of both T= 20°CSpecific heat capacity of water c₂=4.2 J/g°CLet Specific heat capacity of solid be c₁now,heat gained by water = heat lost by solidheat gained/lost = mcΔT∴ m₁c₁ΔT₁ = m₂c₂ΔT₂⇒ 0.05*c₁*(150-20) = 0.1*4.2*(20-11)⇒ 0.05*130*c₁ = 0.1*4.2*9⇒ c₁ = 0.5815 J/g°CAnswer: Specific heat capacity of the solid is 0.5815 J/g°C |
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