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9. ABC is a triangle. D, E and F are the midpoints of AB, AC and BC respectively. Prove that DE and AF bisect each other.​

Answer» LET G be the centroid of TRIANGLE ABC. Given E and F are the MID points of BC and AC respectively. Thus, by mid point theorem, AD∥EFAB=2EFAD=EF (I) (D is mid point of AB)Now, In △ADG and △GEF,∠AGD=∠EGF (Vertically opposite angles)AD=EF (From I)∠ADG=∠GFE (Alternate angles for parallle lines EF and AD)△ADG≅△EGF (ASA rule)Thus, AG=GE (Corresponding sides)Also, DG=GF (Corresponding sides)Thus, AE and DF bisect each other at G.Step-by-step explanation:here ur answerMark as brainliest


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