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9. If p(x) = 32 − 2 + 5 then find p(- 2). |
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Answer» Answer: hu Step-by-step explanation: Question ➡ P(x) = {x}^{2} + 5x + 2P(x)=x 2 +5x+2 Answer ➡ To FIND the VALUES of P(3)+P(2)+P(0) ! For this we have to find the values separately. SUBSTITUTE 3 in place of "x" \begin{lgathered}P(x) = {x}^{2} + 5x + 2 \\ P(3) = {3}^{2} + 5(3) + 2 \\ P(3) = 9 + 15 + 2 \\ P(3) = 26\end{lgathered} P(x)=x 2 +5x+2 P(3)=3 2 +5(3)+2 P(3)=9+15+2 P(3)=26
Hence the value of p(3) = 26 Now, substitute 2 in place of "x" \begin{lgathered}P(x) = {x}^{2} + 5x + 2 \\ P(2) = {2}^{2} + 5(2) + 2 \\ P(2) = 4 + 10 + 2 \\ P(2) = 16\end{lgathered} P(x)=x 2 +5x+2 P(2)=2 2 +5(2)+2 P(2)=4+10+2 P(2)=16
Hence the value of p(2) = 16 Now, substitute 0 in place of "x" \begin{lgathered}P(x) = {x}^{2} + 5x + 2 \\ P(0) = {0}^{2} + 5(0) + 2 \\ P(0) = 0 + 0 + 2 \\ P(0) = 2\end{lgathered} P(x)=x 2 +5x+2 P(0)=0 2 +5(0)+2 P(0)=0+0+2 P(0)=2
Hence the value of p(0) = 2 Now to find the value of P(3)+P(2)+P(0) = P(3)+P(2)+P(0) = 26+16+2 = 44 Therefore value of P(3)+P(2)+P(0) is 44 |
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