9. What will be the normality of a solution obtained by mixing 0.4SN a

1.	9. What will be the normality of a solution obtained by mixing 0.4SN and 0.60N NaOH in the ratio 2: 1 byvolume
Answer» Normality of resulting solution= N1V1+N2V2/V1+V2 Since V1/V2=1/2 = V2=2V1(substituting it in the above given equation) N1=0.45 N, V1=V1 ; N2=0.60,V2=2V1. Now, 0.45V1+0.602V1/V1+2V1 = 0.45V1+1.20V1/3V1 = 1.65 V1/3V1 (V1 gets cancelled) =0.55 N

9. What will be the normality of a solution obtained by mixing 0.4SN and 0.60N NaOH in the ratio 2: 1 byvolume

Answer»

Normality of resulting solution= N1V1+N2V2/V1+V2

Since V1/V2=1/2 = V2=2V1(substituting it in the above given equation)

N1=0.45 N, V1=V1 ; N2=0.60,V2=2V1.

Now, 0.45*V1+0.60*2V1/V1+2V1

= 0.45V1+1.20V1/3V1

= 1.65 V1/3V1 (V1 gets cancelled)

=0.55 N