InterviewSolution
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InterviewSolution
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""_(90)^(234)Th disintegrates to give ""_(82)^(206)Pb as the final product. How many alpha- and beta-particles are emitted during the process? |
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Answer» Solution :Since with the emission of an `ALPHA`-particle, the mass number of the product DECREASES by four units. Thus, number of `alpha`-particles emitted `=(234-206)/(4)=7` Now with the emission of 7 `alpha`-particles, the atomic number decreases by 14 units, i.e., the resulting atomic number will be `90-14=76`. But since Pb has an atomic number of 82, therefore, `6 BETA`-particles will be emitted in order to increase the atomic number from 76 to 82. Thus `""_(90)^(234)Th underset(6beta)overset(7alpha)rarr ""_(82)^(206)Pb` |
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