1.

._(92)U^(235) + n rarrfission product + neutron + 3.20 xx 10^(-11) J. The energy released when 1g of ._(92)U^(235) undergoes fission is

Answer»

`12.75 xx 10^(8) kJ`
`18.60 xx 10^(9) kJ`
`8.21 xx 10^(7) kJ`
`6.55 xx 10^(6) kJ`

Solution :`1g U-235 = (6.023 xx 10^(23))/(235)` ATOMS
`:.` ENERGY released `= 3.2 xx 10^(-11) xx (6.023 xx 10^(23))/(235) J`
`= 8.21 xx 10^(1) J = 8.2 xx 10^(7) kJ`


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