1.

._(95)Am^(241) and ._(90)Th^(234) belongs respectively to

Answer»

`4n + 4n +1` radioactive disintegration series
`4n + 1 and 4n + 2` radioactive disintegration series
`4n + 1 and 4n + 3` radioactive disintegration series
`4n + 1 and 4n` radioactive disintegration series

Solution :In `._(90)Th^(234)` the MASS no. DIVISION by four gives a residue of 1.
In `._(90)Th^(234)` the massno. Division by four gives a residue of 2.


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