1.

96500C electricity is passed through CuSO_(4) the amount of copper precipitated is

Answer»

0.25 mole
0.5mole
1.0mole
2.00mole

Solution :`UNDERSET(1"mole")(CU^(2+))+underset(2"Faraday"=2xx96500C)(2e^(-))rarrCu`
2xx96500C deposits 1 mole of COPPER
96500C deposits 0.5 mole of copper.


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