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`9x^(2) +2hxy +4y^(2) +6x +2fy - 3 = 0` represents two parallel lines. ThenA. `h = 6, f = 2`B. `h =- 6, f = 2`C. `h = 6, f =- 2`D. `h =- 6, f =- 2` |
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Answer» Correct Answer - A::D Since the given equation represents a pair of parallel lines, we have `h^(2) = ab rArr h = +-6` Condition for pair of lines `|{:(9,h,3),(h,4,f),(3,f,-3):}| =0` `rArr 9f^(2) -6hf +36 = 0` For `h = 6, f^(2) -4f +4 =0` or `f =2` For `h =- 6, f^(2)+4f +4 =0` or `f =- 2` |
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