A 0.001 molal solution of [Pt(NH3)4cl4] in water had a freezing point – InterviewSolution

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1.	A 0.001 molal solution of [Pt(NH3)4cl4] in water had a freezing point depression of 0.0054∘. If Kf for water is 1.80, the correct formulation for the above molecule is
Answer» A 0.001 molal solution of $[P t (N H_{3})_{4} c l_{4}]$ in water had a freezing point depression of ${0.0054}^{\circ}$ . If $K_{f}$ for water is 1.80, the correct formulation for the above molecule is

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