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A 0.0020 m aqueous solution os an ionic compound [Co(NH_(3))_(5)(NO_(2))] CI freezes at -0.0732^(@)C. Number of moles of ions which 1 mole of an ionic compound produces on being dissolved in water will be:

Answer»

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Solution :`DeltaT_(f)=i K_(f)m`
`i=((0.0732K))/((1.86Km^(-1))xx(0.0020m))=2`
Since, the ionic compound complete dissociates in aqueous OLUTION, DEGREE of dissociation `(PROP)is ~~1`.
For dissociation, `ALPHA=(i-1)/(n-1)`
`1=(2-1)/(n-1)or n=1+1=2`
No. of mole ions formed=2


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