1.

A 0.004 M solution of Na_(2)SO_(4) is isotomic with a 0.01 M solution of glucose at same temperature. The apparent degree of dissociation of Na_(2)SO_(4) is:

Answer»

`25%`
`50%`
`75%`
`85%`

Solution :Since the SOLUTIONS are ISOTONIC, They have the same osmotic pressure also.
`pi_(Na_(2)SO_(4))=pi_("glucose")`
`ixx0.004 RT = 0.01 RT`
`i=0.01/0.004=2.5`
`Na_(2)SO_(4)hArr2Na^(+)+SO_(4)^(2-)`
`ALPHA=(i-1)/(n-1)=(2.5-1)/(3-1)=1.5/2`
=0.75 or 75%


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