1.

A 0.004 M solution of Na_(2)SO_(4) is isotonic with 0.010 M solution of glucose at same temperature. The percentage dissociation of Na_(2)SO_(4) is

Answer»

0.25
0.5
0.75
0.85

Solution :`{:(Na_(2)SO_(4) ,hArr, 2Na^(+)+, SO_(4)^(2-)),((0.004-X),, 2X, x):}`
Since both SOLUTIONS are ISOTONIC, therefore, `0.004 + 2x = 0.01, x = 3 xx 10^(-3)`
`:.` % DISSOCIATION `= (3 xx 10^(-3))/(0.004) xx 100 = 75`


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