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A 0.01 D^(**) solution of KCl has a specific conductance value of 0.00141 mho cm^(-1). A cell filled with this solution has a resistance of 42156 ohms. (a) What is the cell constant ? (b) The same cell filled with a solution of Hcl has a resistance of 1.0326 ohms. What is specific conductivity of the HCl solution ? |
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Answer» Solution :(a) Cell constant `= ("specific conductance")/("conductance")` `= ("specific conductance")/("1/resistance")` `= (0.00141)/(1//4.2156) = 0.00594 CM^(-1)`. (b) Conductance of HCL solution `= (1)/(1.0326)` mho. Sicne the same cell is USED, we SHALL take the same value of cell constant in this case. SP. conductance = cell constant `xx` conductance `= 0.00594 xx (1)/(1.0326)` `= 0.00575 "mho cm"^(-1)`. |
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