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A 0.01 H inductor and `sqrt(3)pi Omega` resistance are connected in series with a 220 V, 50 Hz AC source. The phase difference between the current and emf isA. `pi/2rad`B. `pi/6` radC. `pi/3` radD. *- |
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Answer» Correct Answer - B `phi = tan^(-1)((X_(L))/R) = tan^(-1)((2pivL)/R)` `=(tan^(-1))((2pi xx 50xx0.01))/(sqrt(3pi))=tan^(-1)(1/(sqrt(3))) = pi/6rad` |
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