1.

A 0.01 M solution of glucose in water freezes at- 0.0186^(@)C. A 0.01 M solution of NaCl in water will freeze at

Answer»

`0^(@)C`
`0.0186^(@)C`
`-0.0186^(@)C`
`-0.0372^(@)C`

Solution :Depression in freezing POINT will be ALMOST DOUBLE because the NUMBER of particles of 0.01 M NaCl are double than 0.01 M glucose.


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