1.

A 0.025 m solutio of mono basic acid had a freezing point of 0.06^(@)C. Calculate K_(s) for the acid K_(f) for H_(2)O=1.86^(@) "molality"^(-1).

Answer»

Solution :For mono basic acidHA
`HA hArr H^(+)A^(-)`
`{:(1,0,0),((1-alpha),alpha,alpha):}` "" i= (1+alpha)`
From Ostwald Dilution Law,`K_(a)=(CALPHA^(2))/((1-alpha))`
`DeltaT_(f)=K_(f)xx(i)`
`rArr 0.06=1.876xx0.025xx(1+alpha)`
`:.(1+alpha)=(0.06)/(0.0465)`
`:. alpha=0.029, C=0.025M`
`K_(s)=(alpha^(2))/((1-alpha))`
From equation (i) `K_(a)=(0.025xx(0.029)^(2))/((1-0.029))`
`=2.96xx10^(-3)`


Discussion

No Comment Found

Related InterviewSolutions