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A 0.05 L sample of 0.2 M aqueous hydrochloric acid is added to 0.05 L of 0.2 M aqueous ammonia in a calorimeter. Heat capacity of entire calorimeter system is 480 J/K. The temperature increase is 1.09 K. Calculate `Delta_(r )H^(@)` in kJ/mol for the following reaction : `HCl(aq.)+NH_(3)(aq.)rarrNH_(4)Cl(aq.)`A. `-52.32`B. `-61.1`C. `-55.8`D. `-58.2`

Answer» Correct Answer - A
m mole of acid `=0.05 xx 0.2 =0.01`
`Delta_(r )H^(@)=-(480xx1.09)/(0.01 xx 1000)=-52.32 " kJ"//"mol"`


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