1.

A 0.1 molal aqueous solution of a weak acid is 30% ionized. If K_(f) for water is 1.86^(@)C//m, the freezing point of the solution will be

Answer»

`-0.18^(@)C`
`-0.54^(@)C`
`-0.36^(@)C`
`-0.24^(@)C`

Solution :`{:(HA,RARR,H^(+),+,A^(-)),(1-ALPHA,,alpha,,alpha),(1-0.3,,0.3,,0.3):}`
`THEREFORE i=(1-0.3)+0.3+0.3=1.3`
`DeltaT_(f)=iK_(f)m=1.3xx1.86xx0.1=0.2418`
`T_(f)=0-0.2418^(@)C=-0.2418^(@)C~=-0.24^(@)C`.


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