1.

A 0.1M solution of sodium acetate was prepared. The K_(h)=5.6xx10^(-10) . Then :

Answer»

The degree of HYDROLYSIS is `7.48xx10^(-6)`
the `[OH^(-)]` concentration is `7.48xx10^(-3)M`
the `[OH^(-)]` concentration is `7.48xx10^(-6)M`
the pH is APPROXIMATELY 8.88

Answer :c,d


Discussion

No Comment Found

Related InterviewSolutions