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A 1.0 cm wire carrying a current of 30 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire ? |
Answer» Solution : Consider MAGNETIC FIELD `vecB` produced along the axis of a current carrying LONG SOLENOID. As per the statement, magnetic force exerted on length I of a wire carrying current I, placed inside the solenoid perpendicular to its axis is, `F=IlBsintheta` = `(10)(0.03)(0.27)sin90^(@)` `F=8.1xx10^(-2)N` |
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