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A 1.0 m long metallic rod is rotated with an angular frequency of "400 rad s"^(-1) about an axis normal to the rod passing through its one end. The other end of the rod is in contact with a circular metallic ring. A constant and uniform magnetic field of 0.5 T parallel to the axis exists everywhere. Calculate the emf developed between the centre and the ring. |
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Answer» Solution :Here EMF induced between centre and rim of ring is the emf induced across the given rod. This emf is, `EPSILON=1/2B omegaL^2` `=1/2xx0.5xx400xx(1)^2` `THEREFORE epsilon`=100 V |
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